Quote (FamilyGuyViewer @ Feb 19 2014 12:24am)
first two, i would do mesh analysis. but the first one will have a super mesh in it so becareful wit that.
for number 3, use KCL (current in = current out) then use the fact that, there is resistors in parallel so voltage across those resistors are equal.
4th one, simplify the circuit and use voltage across resistors are equal.
Yeah, I don't know mesh analysis yet though.

The first two are the only ones I have left to go.
Problem 3I figured out the voltage was the same, 120V, across the 3 in parallel on the third problem, the used a combination on Ohm's Law and the Power given on the third resistor to use p=iv to find the rest of it. So got the third one.
Actually, for this problem (3) I was unsure if the voltage would remain 120 V across the 3 in parallel since the voltage source would also be in parallel with them... is that a correct assumption?Problem 44th one, not sure if I did it right but I simplified the circuit. Used the equation, V1 = (R_eq/R_total)*(Vs)
Vs = 3 V
R_eq = 50 ohm (just the 75 ohm and 150 ohm resistor in parallel)
R_total = 135 ohm (the resistor equivalent of the entire circuit.)
I got a small number though, V1 = 1.11V, so not sure if it's correct.
*Then for V2 I found the initial current by using V=iR from the R_total and 3V initial voltage, I got 0.222A.
Then found the current through the 30 ohm resistor using the current division equation, i_30 = (R_total/R_30)*(i_s)
i_s = initial current = 0.222A
R_total = 135 ohm
R_30 = 30ohm
I got 1A for the current in the 30 ohm resistor and then from there I just used Ohm's Law to for the voltage, V=iR = (1A)(30ohm) = 30V
Not sure if that's the right way but whatever.
Now I just need help on the first two. I'll probably figure them out by myself but if anyone has any help that would be cool.
I really need to solve these just by using Ohm's Law, Kirchoff's current/voltage Law, Series/Parallel, Current/Voltage division.This post was edited by TheTown on Feb 19 2014 12:23am