"ilvl = int(.4 * clvl) + int(.4 * ilvl)
This recipe rerolls the rare item, resetting all the modifiers. The item level is lowered, but can still be fairly high, if the item and the character rolling it are high level. (Level 80 character and level 80 item would turn into 32 + 32 = ilvl 64.)
Note that the cube is only 12 spaces in size, and with 6 perfect skulls there's no room for 2x4 items such as large bows/xbows, polearms, spears, etc."


so in not sure if i understand this properly or not but say hypothetically im a lvl 80 character and im rerolling a rare lets just say a lvl 80 like in the description above and say i kept rerolling the item would my finished ilvls go like this

80
64
56.7
55.04
54.016
53.6064
53.44256
53.377024
53.33508096
53.3403238
53.3361295
53.334518
53.3337807
53.33335123
53.3334049
53.333362
53.33333448
ect so you basically have a infinite amount of chances to roll a ilvl 53 item like this? or am i doing this wrong? also is there like rounding up or down in the way the game computes this stuff at all? any sort of guidance would be greatly appreciated

Quick question you say? Tl:dr - that ain’t a quick question

ok ok so say i answered the questions in rapid succession it should go something like this

so you basically have a infinite amount of chances to roll a ilvl 53 item like this? ........ yes

or am i doing this wrong? .............. yes or no (im thinking yes is the answer but the math should generally work out to be the same ilvl even if my math is off because of the question below)

also is there like rounding up or down in the way the game computes this stuff at all? ........... (i think the is but im not sure how it works )

This post was edited by icecoldblood on Jul 17 2022 08:04pm