hey now! GTFO MY HEAD

Jizz all over your notes for the standard definition of a derivative cuz we prolly won't see that shit again for awhile

Sounds hawt, but I have yet to fully understand the chain rule lol.

Which parts of it? The initial part? Or Implicit differentiation?

My professor made it really complicated

I understand how to do the basic chain rule, but he keeps changing around the symbols and leaves dy/dx next to polynomials, and I'm like what am I supposed to do?


Yeah Implicit Differentiation.

like Bounty

Better than that. Absorbs better like ShamWow!

Are you getting this camera guy?

Absorbs beatings better than the whore beaten up by the ShamWow guy?

Absorbs your penis into a blackhole


The feeling is so unbelievable and extraordinaire.

as far as implicit differentiation,


If you are working with just a basic function, lets say f(x) = 3x + 4y

you can think of it as


y = 3x + 4y


taking the derivative with respect to x (that's just the wordy version of saying D/DX) of both sides of the equation would be


y (D/DX) = 3x (D/DX) + 4y (D/DX)

as for the left hand side of that equation, you get y(D/DX) = DY/DX

and the derivative of the right hand side, 3x is 3 and the derivative of 4y would be 4

BUT

because we are taking the derivative with respect to X, we can't just say d/dx of 4y = 4 (the variables do not match!)

Instead, you have to apply a chain rule and say that


D/DX of 4y = 4(DY/DX)

essentially, when you are taking the derivative of something with respect to like, X, Y, T, (D/DX, D/DY, D/DT [which you see a lot in physics]) whatever...if the variables in the function don't match up with what the derivative is, you have to use implicit differentiation.

and so you would wind up, in my example, with

dy/dx = 3 + 4(dy/dx)

and that's usually as far as you have to go, though sometimes they will give you a value for dy/dx etc.

This post was edited by Eep on Oct 25 2011 10:54pm