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Jan 3 2015 08:34pm
Quote (carteblanche @ Jan 3 2015 09:31pm)
i used to think that too, but mathematically 0.9 repeating is actually equal to 1, not just approaching or close to it.


if it was equal it would be 1, it is not 1 it is .99999....\

using that logic you would state there is no intelligent life in the universe, cuz we are the .000000....1 and counting, SO FAR :P

This post was edited by yupitsmeh on Jan 3 2015 08:36pm
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Jan 3 2015 08:35pm
Quote (yupitsmeh @ Jan 3 2015 09:30pm)
like to think so but factorials have no place in order of operation or as you say pedmas


it's a function. it works just fine.
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Jan 3 2015 08:36pm
Quote (yupitsmeh @ Jan 3 2015 09:34pm)
if it was equal it would be 1, it is not 1 it is .99999....


not sure if trolling or srs. if srs, yes it's one. you can prove it many ways. this is probably the easiest way:

0.9... = n
0.3... + 0.3.... + 0.3... = n
1/3 + 1/3 + 1/3 = n
3 / 3 = n
1 = n
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Jan 3 2015 08:41pm
Quote (carteblanche @ Jan 3 2015 09:36pm)
not sure if trolling or srs. if srs, yes it's one. you can prove it many ways. this is probably the easiest way:

0.9... = n
0.3... + 0.3.... + 0.3... = n
1/3 + 1/3 + 1/3 = n
3 / 3 = n
1 = n


its been awhile but isnt it a infinite geometric series

This post was edited by yupitsmeh on Jan 3 2015 08:43pm
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Jan 3 2015 08:43pm
Quote (carteblanche @ Jan 3 2015 10:36pm)
not sure if trolling or srs. if srs, yes it's one. you can prove it many ways. this is probably the easiest way:

0.9... = n
0.3... + 0.3.... + 0.3... = n
1/3 + 1/3 + 1/3 = n
3 / 3 = n
1 = n


mindfuked

:o
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Jan 3 2015 08:44pm
Quote (carteblanche @ Jan 3 2015 10:36pm)
not sure if trolling or srs. if srs, yes it's one. you can prove it many ways. this is probably the easiest way:

0.9... = n
0.3... + 0.3.... + 0.3... = n
1/3 + 1/3 + 1/3 = n
3 / 3 = n
1 = n





You can't use as a given the .9 = n

Because .99999999999999999999999999999999999999999999999..... does NOT = .9



/e ....and you can't use 3's of any kind at all, in a clock made of 9's, or in a proof that .99999999999999999999999999999999.... = 1


yes, it's true that 1/3 + 1/3 +1/3 =1 ...but ONLY if you leave them in fractional form. If you work out 1/3 it = .3333333333333333333333333..... which still leaves us with the same issue x approaching 1, but never getting there.

This post was edited by Ghot on Jan 3 2015 08:48pm
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Jan 3 2015 08:50pm
Quote (yupitsmeh @ Jan 3 2015 09:41pm)
its been awhile but isnt it a indefinite geometric series


infinite* yes.

.999... = 9/10 + 9/100 + 9/1000 + 9* 1/10^i
= sum ( 9*1/10^i)

using sum = ar/(1-r):
= 9*(1/10) / (1 - 1/10)
= (9/10) / (9/10)
= 1

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Jan 3 2015 08:55pm
Quote (Ghot @ Jan 3 2015 09:44pm)
You can't use as a given the .9 = n

Because .99999999999999999999999999999999999999999999999..... does NOT = .9



/e  ....and you can't use 3's of any kind at all, in a clock made of 9's, or in a proof that .99999999999999999999999999999999....  = 1


yes, it's true that 1/3 + 1/3 +1/3 =1  ...but ONLY if you leave them in fractional form.  If you work out 1/3 it = .3333333333333333333333333..... which still leaves us with the same issue  x approaching 1, but never getting there.


i used .9.... where the ... at the end meant repeating. also, i'm letting n represent 0.9 repeating. sorry about the notation.

0.3... [0.3 repeating] is EXACTLY equal to 1/3, as well. it's just difficult to represent using the base 10 model. you can use base 3 if you'd like. in which case 1/3 + 1/3 + 1/3 is 0.1 + 0.1 + 0.1 = 1.0

if you don't like this proof, i can prove it in other ways as well. but i dont feel like it at the moment, so i'll just link you to a wiki article with a few proofs instead.

http://en.wikipedia.org/wiki/0.999...

This post was edited by carteblanche on Jan 3 2015 08:56pm
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Jan 3 2015 08:56pm
First off Wikipedia doesn't have a degree in Math....2nd off, here's the clock fixed....







This post was edited by Ghot on Jan 3 2015 08:58pm
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Jan 3 2015 08:56pm
so the sum of all natural numbers is -1/12?
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