Quote (Ghot @ Jan 2 2015 05:51am)

http://i.imgur.com/wFJMw3K.jpg



http://i.imgur.com/AXxeuHV.jpg



http://i.imgur.com/Tam9WJy.png

Quote (noob_whacker @ Jan 3 2015 08:08pm)

trigonometric clock

eh fuk that class so annoying

although it actually was a legit class and learned some decent stuff

but yet i prob forgot most lol

Quote (yupitsmeh @ Jan 3 2015 08:17pm)

show work for number 5

Quote (carteblanche @ Jan 3 2015 09:28pm)

pretty sure he dun goofed. roof a little too looong

Quote (Ghot @ Jan 3 2015 08:53pm)

Yep it should be ((sqrt 9)!) - 9/9  ...which would = 5


/e  The top of the square root symbol, should have stopped just before the exclamation point.  Cause 3! = 6

/ee 3! = 3*2*1....but 9! = 362880


I found an easier way to generate a 5 using only 9's....


(9+9) - Sqrt 9  ...ALL divided by sqrt 9  ...or....

(18-3)/3 = 5



http://i.imgur.com/ZlGEJpJ.jpg

Quote (yupitsmeh @ Jan 3 2015 09:26pm)

like that one better

factorial can only be used with integers, a sq root isnt an integer

Quote (yupitsmeh @ Jan 3 2015 10:26pm)

like that one better

factorial can only be used with integers, a sq root isnt an integer

Quote (carteblanche @ Jan 3 2015 09:28pm)

except that sqrt(9) is an integer?

Quote (Ghot @ Jan 3 2015 09:29pm)

Well  technically the 7 o'clock thing doesn't work either...it would be x approaching 7...forever...but never reaching it.

Quote (Ghot @ Jan 3 2015 09:29pm)

Well  technically the 7 o'clock thing doesn't work either...it would be x approaching 7...forever...but never reaching it.


/e  Unless you applied the rounding function to the .999999999999999999999999999999999999999999999999999999999999999999999.....