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Flippi
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#571
Jan 16 2011 07:01am
Klausur lief super, danke an alle. Die Note lasse ich euch selbstverständlich zukommen.
Ghostfacer
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#572
Jan 16 2011 08:40am
f(x)=(x²-2x)*e^(0,5x)
f'(x)=e^(0,5x)*(-1+x²)
hab den verdacht dass das falsch ist
kann mir jmd helfen?
Gottesritter
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#573
Jan 16 2011 08:45am
Quote (Ghostfacer @ 16 Jan 2011 14:40)
f(x)=(x²-2x)*e^(0,5x)
f'(x)=e^(0,5x)*(-1+x²)
hab den verdacht dass das falsch ist
kann mir jmd helfen?
(0,5x²+3x-2)* e^0,5x
abcmaster
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#574
Jan 16 2011 08:48am
http://www.wolframalpha.com/input/?i=(x%C2%B2-2x)*e^(0.5x)+
Gottesritter
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#575
Jan 16 2011 08:50am
Quote (abcmaster @ 16 Jan 2011 14:48)
http://www.wolframalpha.com/input/?i=(x-2x)*e%5E(0.5x)+
failed
abcmaster
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#576
Jan 16 2011 08:58am
Quote (Gottesritter @ 16 Jan 2011 15:50)
failed
eZ abcmastered
Ghostfacer
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#577
Jan 16 2011 09:04am
Quote
(0,5x²+3x-2)* e^0,5x
(2x-2)*e^(0,5x) + (x²-2x)*e^(0,5x) *0,5
ist als zwischenschritt aber richtig?
Gottesritter
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#578
Jan 16 2011 09:07am
Quote (Ghostfacer @ 16 Jan 2011 15:04)
(2x-2)*e^(0,5x) + (x²-2x)*e^(0,5x) *0,5
ist als zwischenschritt aber richtig?
(0,5x²+x-2)*e^0,5x
tor_zero
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#579
Jan 16 2011 09:08am
Quote (Gottesritter @ Jan 16 2011 03:45pm)
(0,5x²+3x-2)* e^0,5x
ist zwar falsch aber egal
Gottesritter
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#580
Jan 16 2011 09:08am
Quote (tor_zero @ 16 Jan 2011 15:08)
ist zwar falsch aber egal
Quote (Gottesritter @ 16 Jan 2011 15:07)
(0,5x²+x-2)*e^0,5x
nuff said
eZ gottesrittered
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