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#6541
Oct 24 2009 06:43pm
f(x)= I R always free :0
x=always free
free=hw
Z=dy/dx[3^8]/[f(-1)]
f(-1)={[(2-8^2)+24]/2}/19-1

Solve for{[f(x)]/[(9000+30^2)+Z]}

this is y I R always hw
except my math problem is f(-1) times harder.
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#6542
Oct 24 2009 06:45pm
Quote (ethan_u @ 24 Oct 2009 17:43)
f(x)= I R always free :0
x=always free
free=hw
Z=dy/dx[3^8]/[f(-1)]
f(-1)={[(2-8^2)+24]/2}/19-1

Solve for{[f(x)]/[(9000+30^2)+Z]}

this is y I R always hw
except my math problem is f(-1) times harder.


i will don8 if some 1 solved this :0
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#6543
Oct 24 2009 06:46pm
Quote (ethan_u @ Oct 24 2009 06:45pm)
i will don8 if some 1 solved this :0


ask homework section?
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#6544
Oct 24 2009 06:54pm
Quote (LastZodiac @ 24 Oct 2009 17:46)
ask homework section?


this gc only :D
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#6545
Oct 24 2009 07:06pm
fuck UL is a no go
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#6546
Oct 24 2009 07:24pm
Quote (ethan_u @ 24 Oct 2009 17:43)
f(x)= I R always free :0
x=always free
free=hw
Z=dy/dx[3^8]/[f(-1)]
f(-1)={[(2-8^2)+24]/2}/19-1

Solve for{[f(x)]/[(9000+30^2)+Z]}

this is y I R always hw
except my math problem is f(-1) times harder.


answer is 4
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#6547
Oct 24 2009 07:26pm
Quote (LezAzul @ Oct 24 2009 07:24pm)
answer is 4


lies
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#6548
Oct 24 2009 08:01pm
Quote (mw14000 @ 24 Oct 2009 18:26)
lies


who wanted my bro's number he said he doesn't mind if i give it out =o
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#6549
Oct 24 2009 08:04pm
Quote (LezAzul @ Oct 24 2009 08:01pm)
who wanted my bro's number he said he doesn't mind if i give it out =o


reano
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#6550
Oct 24 2009 08:10pm
Quote (LezAzul @ Oct 25 2009 10:01am)
who wanted my bro's number he said he doesn't mind if i give it out =o


me! and henry!
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