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#1
Nov 23 2015 10:18am
naszoval van egy ilyen funkciom
(x^2*arctan(x))/(2x+1)
aminek keresem az aszimptotait, foleg azt az atlosat, amelyik fele akkor megy, ha x -vegtelen fele
szamitasaim alapjan elvileg y=(-pi/4*x)-(-1/8*(4+pi)), de nem tunik jonak

This post was edited by SummertimeClothes on Nov 23 2015 10:29am
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#2
Nov 23 2015 10:20am
5
a megoldas
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#3
Nov 23 2015 10:25am
pls help
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#4
Nov 23 2015 10:26am
arctan xD
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#5
Nov 23 2015 10:26am
Quote (MarcusD @ 23 Nov 2015 17:26)
arctan xD


?.
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#6
Nov 23 2015 10:33am
420
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#7
Nov 23 2015 10:42am
Tok szar erzes hogy mindent elfelejtettem pedig regen jo matekos voltam :(
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#8
Nov 23 2015 10:43am
huh
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#9
Nov 23 2015 10:50am
Quote (SummertimeClothes @ Nov 23 2015 05:18pm)
naszoval van egy ilyen funkciom
(x^2*arctan(x))/(2x+1)
aminek keresem az aszimptotait, foleg azt az atlosat, amelyik fele akkor megy, ha x -vegtelen fele
szamitasaim alapjan elvileg y=(-pi/4*x)-(-1/8*(4+pi)), de nem tunik jonak


wolframalfa
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#10
Nov 23 2015 10:53am
Quote (TresholdOfUniverse @ 23 Nov 2015 17:50)
wolframalfa


azzal kezdtem, kettot megtalal, a harmadikat nem
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