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Views: 804Replies: 32Track Topic
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#11
Nov 23 2015 12:01pm
Quote (SummertimeClothes @ Nov 23 2015 05:18pm)
naszoval van egy ilyen funkciom
(x^2*arctan(x))/(2x+1)
aminek keresem az aszimptotait, foleg azt az atlosat, amelyik fele akkor megy, ha x -vegtelen fele
szamitasaim alapjan elvileg y=(-pi/4*x)-(-1/8*(4+pi)), de nem tunik jonak


pont ebböl vizsgazok holnap, es fogalmam sincs hogy müködik
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#12
Nov 23 2015 12:28pm
Felette picibkettes.
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#13
Nov 23 2015 12:37pm
help pls
levezetes nem kell
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#14
Nov 23 2015 12:38pm
bumppal segítek
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#15
Nov 23 2015 12:46pm
miért nincs 2015 végén olyan honlap ahova bármi hasonló undormányt beírsz és levezeti neked ?
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#16
Nov 23 2015 12:48pm
Quote (SummertimeClothes @ 23 Nov 2015 20:37)
help pls
levezetes nem kell


nem?
akkor 3
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#17
Nov 23 2015 12:49pm
Quote (sylke @ 23 Nov 2015 19:48)
nem?
akkor 3


nem
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#18
Nov 23 2015 12:50pm
Quote (SummertimeClothes @ 23 Nov 2015 19:49)
nem


hanem
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#19
Nov 23 2015 12:52pm
http://www.wolframalpha.com/input/?i=asymptotes+%28x%5E2*arctan%28x%29%29%2F%282x%2B1%29
mondom, ez a ketto megvan mar, de kene legyen megegy, amikor x -vegtelen fele megy, amit nem ad ki
ne bogjetek, segitsetek

This post was edited by SummertimeClothes on Nov 23 2015 12:55pm
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#20
Nov 23 2015 12:55pm
kerj Grabovoj szamsort
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