Quote (sMACKTRiCKz @ Oct 4 2011 06:32pm)
eZ for i) and ii)
we know that if m^ - n^2 is even you have basically 3 cases
m^2 = even, n^2 = even.
m^2 = odd n^2 = odd
so from proof in #3 we know that this also leaves us wiht the cases
m = even, n= even
m = odd, n= odd
so then we know even - even = even and odd - odd = even, so proven (yes you have to word this alot better)
basically same thing applies for iii), since even + even = even, odd +odd = odd
hmmm ty
took break to eat some food, gonna try to show it in nice symbolic shit in a second