instead of making multiple threads every time I have a small question, I'm just going to post questions here (or anyone could too).


for(x=0;x<3;x++)
{
System.out.println("do you want met o draw a simple house for you? ");
answer=keyboard.next();

if(answer==yes)
good=true;

else if(answer==no)
end=true;
}


it's as if it completely ignores the 2 if statements (I initialized the variables). Is my syntax wrong? Thank you

is that the EXACT code? line by line?


If not, you need to post ALL of the code, exactly as it appears in your source. Also, make sure to use code tags for formatting and readability



This post was edited by Eep on Oct 22 2015 06:10pm

i assume those are strings. use .equals instead of ==

== works ok when comparing literals, but reading input from keyboard isn't a literal.

That's part of the code, I didn't want to post all of it and make it look complicated for you guys, but yes carteblanche gave me the answer thank you. And yea next time I'll use the quote format thanks.



Thank you!

This. Iirc corretly what you were actually comparing to there was the location address of your string.

hello,
let's say i create a 2D integer array for tictactoe in this format:



how would I be able to insert the X or the O as characters? It prints it as the unicode value

thanks

This post was edited by kyle_lowry2 on Oct 28 2015 09:58pm

Characters can be referenced by integers and it will return a character based on the unicode value.

There is a primitive data type for characters.
https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

This post was edited by ROM on Oct 29 2015 05:26am