Debug Problem With Python - Topic

Member

Posts: 10,812

Joined: Oct 15 2009

Gold: Locked

Warn: 20%

Apr 1 2014 09:00am

Code

c_text_list=[127, 86, 71, 71, 78, 23, 118, 71, 69, 94, 91, 23, 113, 88, 88, 91, 16, 68, 23, 115, 86, 78, 22, 22, 22]
p_text_string=""
for entry in c_text_list:
p_text_string += chr(entry^55)

print p_text_string

0n35

Member

Posts: 11,610

Joined: Oct 28 2008

Gold: 1,795.00

Apr 1 2014 12:36pm

print needs ()

zeroRooter

Member

Posts: 21,211

Joined: May 22 2009

Gold: 9,036.90

Apr 1 2014 02:22pm

Quote (0n35 @ Apr 1 2014 01:36pm)

print needs ()

only if python3

0n35

Member

Posts: 11,610

Joined: Oct 28 2008

Gold: 1,795.00

Apr 1 2014 02:34pm

Quote (zeroRooter @ Apr 1 2014 02:22pm)

only if python3

no

I can import print to use it like in py2.x

from __future__ import print_function

But to pep3105 standards the statement has been removed

j0ltk0la

Member

Posts: 62,215

Joined: Jun 3 2007

Gold: 9,039.20

Apr 2 2014 03:43am

Don't even need to import from future, Print is already a function in 2.7.6

Code

Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation. All rights reserved.

C:\Users\urafag>python
Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> print('dum')
dum
>>>

0n35

Member

Posts: 11,610

Joined: Oct 28 2008

Gold: 1,795.00

Apr 2 2014 04:06am

Quote (killgoreisleet @ Apr 2 2014 03:43am)

Don't even need to import from future, Print is already a function in 2.7.6

Code

In Python 2.x print is a special statement, not a function

This is why it can't be used like: lambda x: print x
Note that (expr) does not create a Tuple (it results in expr), but "," does.

j0ltk0la

Member

Posts: 62,215

Joined: Jun 3 2007

Gold: 9,039.20

Apr 2 2014 04:55am

Quote (0n35 @ Apr 2 2014 04:06am)

In Python 2.x print is a special statement, not a function

This is why it can't be used like: lambda x: print x
Note that (expr) does not create a Tuple (it results in expr), but "," does.

It seems to work like a function, in the way it works in Python 3+

Code

>>> a = range(0,4)
>>> a
[0, 1, 2, 3]
>>> for i in a:
... print(i+i)
...
0
2
4
6
>>>

You are right, I believe in Python the “,” determines if something is a Tuple more so than the “()”

I think there might be something wrong with lambda, the way it was made, but I am probably wrong.

The way Print is working currently in 2 may be a way to help ease the conversion to 3.

Go Back To Programming & Development Topic List