How does it work? For me it looks like magic '-', example;

I got a function



and when I call it like this



Why can I rename min/max to what ever I want and it still compiles correctly? What information am I missing?

Thanks

I just ran into another problem -..-

"Implement the function read_seq that reads a senquence of n≥0 non-negative integers into an array V. Ignore any negative values entered by the user"

So bacisly, some code that ignores negative numbers and add the other into the array.. how do I still continue typing after negative numbers have been typed in? I guess I need to use string?

The function

& - pretty much means that you're using a pointer to a variable, so instead of having the program go "here's the value for x, work on it", it says "here's the location where x is, do whatever you want to it"

In every function the variable names are locally declared, so if you do


you can plug any integer values and variables from any other function in there.

The min and max you're declaring are in the caller's scope. Their name are irrelevant to the callee's scope. Invoking a routine that takes arguments by reference is transparent on the caller side, i.e. it doesn't change how you call, only how the callee deals with the arguments. The difference is sensible however. Using classic arguments, the callee with declare the variables within its own scope, copy the data from the arguments to it, and those will expire when the callee exits its scope. When the arguments are passed by reference, the callee creates pointers and points them to the memory location of the arguments it received by reference. In this case all modifications done to the arguments will be applied to the original.



What do strings have to do in this? You have an array of integer, you cycle through it with a for or a while loop and only save the positive values.

This post was edited by flyinggoat on Oct 20 2013 04:15am