i need to use structure

first i will ask the users what he wants to do:
enter new employee(part time,full time)(add first name,last name,idnumber,gender,salaray)
check all employees
or quit

sounds like a good starting point. now what do you need help with?

i need if else to see which option the users picked
the arrays to store the info for new users
and array to check the records

ok...and what part of that do you need help with?

i need help with struct
getting the info about employee and storing it

what code do you have so far?

here are examples for how to do a struct:
http://www.cplusplus.com/doc/tutorial/structures/

the attributes you want are part time/full time, first name,last name,idnumber,gender,salary

here are some examples of how to get input from a user:
http://www.cplusplus.com/doc/tutorial/basic_io/

here are some examples of how to use arrays:
http://www.cplusplus.com/doc/tutorial/arrays/

#include <iostream>
using namespace std;

int main ()
{
typedef struct employee
{
public:
char fname[20];
char lname[20];
int idnumber ;
char gender ;
int salary ;
};

employee ftemployee[100], ptemployee[100] ;



int n;

cout << "\n==================== ";
cout << "\n<1>Press 1 to add new employee ";
cout << "\n<2>Press 2 to print All Emplyoees ";
cout << "\n<3>Enter anything to quit: ";
cout << "\n==================== \n";
cin >> n;

if ( n==1 ){

cout << "/Enter first name: " << ftemployee.fname;
cout << "/Enter last name: " << ftemployee.laname;
cout << "/Enter id number: " << ftemployee.idnum;
cout << "/Enter gender: " << ftemployee.gender;
cout << "/Enter salary: " << ftemployee.salary;




}
else if (n==2 ){

cout << "\nyou enteredt 2 \n";
}
else {

cout << "\nNot matching any of the choices \n";
cout << "You entered---- " << n << "\n";
}

system("pause");
return 0;
}


i was testing the if else loop so i have some parts left from that

See I told you someone would answer.

yep

thanks
forgot to udpate this thread
did it
had to use few more if statements
and put (1) after struct