Need Help On Java Homework - Topic

Member

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Joined: May 4 2010

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Feb 14 2013 09:08am

I need to use a case statement in the while loop to identify 'A', 'E', 'I', 'O', 'U', and 'Y' as vowels, but I don't believe I know how too. I've been looking through my 'Absolute Java' book and notes, but I'm totally stumped.

Code

public class ABC {

public static void main(String[] args) {

char alphabet = 'A';

while (alphabet <= 'Z')
{
System.out.println(alphabet + " is a consonant");
alphabet++;
}

}
}

Schwag

Member

Posts: 2,579

Joined: Jun 1 2012

Gold: 1,524.00

Feb 14 2013 09:51am

Somewhat pseudocode, but hope it helps you:

Code

for each (char c)
{
switch (c)
{
case 'A':
// do something
break;
case 'E':
// do something
break;
case 'I':
// do something
break;
case 'O':
// do something
break;
case 'U':
// do something
break;
case 'Y':
// do something
break;
default:
// default case (any other character)
}
}

This post was edited by Schwag on Feb 14 2013 09:52am

LetsG0Blue

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Posts: 9,274

Joined: May 4 2010

Gold: 0.01

Feb 14 2013 10:06am

I'm here but it's just printing everything out to be a consoant

Code

public class ABC {

public static void main(String[] args) {

char alphabet = 'A';

while (alphabet <= 'Z')
{
alphabet++;
System.out.println(alphabet + "is a consonant");
}

switch (alphabet)
{
case 'A':
System.out.println(alphabet + " is a vowel");
break;
case 'E':
System.out.println(alphabet + " is a vowel");
break;
case 'I':
System.out.println(alphabet + " is a vowel");
break;
case 'O':
System.out.println(alphabet + " is a vowel");
break;
case 'U':
System.out.println(alphabet + " is a vowel");
break;
case 'Y':
System.out.println(alphabet + " is a vowel");
break;
}

}

}

DirtyRasa

Member

Posts: 2,478

Joined: Jan 4 2007

Gold: 7,545.00

Feb 14 2013 10:10am

You need to put the switch inside of the While loop.

Code

public class ABC {

public static void main(String[] args) {

char alphabet = 'A';

while (alphabet <= 'Z')
{

switch (alphabet)
{
case 'A':
System.out.println(alphabet + " is a vowel");
break;
case 'E':
System.out.println(alphabet + " is a vowel");
break;
case 'I':
System.out.println(alphabet + " is a vowel");
break;
case 'O':
System.out.println(alphabet + " is a vowel");
break;
case 'U':
System.out.println(alphabet + " is a vowel");
break;
case 'Y':
System.out.println(alphabet + " is a vowel");
break;

default:
System.out.println(alphabet + "is a consonant");
break;
}
}

alphabet++;

}

}

This post was edited by DirtyRasa on Feb 14 2013 10:10am

LetsG0Blue

Member

Posts: 9,274

Joined: May 4 2010

Gold: 0.01

Feb 14 2013 10:12am

$(*($#*$(# damn I was so close.

Thanks a lot!

DirtyRasa

Member

Posts: 2,478

Joined: Jan 4 2007

Gold: 7,545.00

Feb 14 2013 10:13am

You could even clean it up and do something like this:

Code

public class ABC {

public static void main(String[] args) {

char alphabet = 'A';

while (alphabet <= 'Z')
{

switch (alphabet)
{
case 'A':
case 'E':
case 'I':
case 'O':
case 'U':
case 'Y':
System.out.println(alphabet + " is a vowel");
break;

default:
System.out.println(alphabet + "is a consonant");
break;
}
}

alphabet++;

}

}

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