what does arr[7] +=200; and arr[4] --; mean and what does it change it to?o.O

#include <iostream>
int main()
{
int arr[10];

for (int j = 2; j <= 8; j++)
arr[j] = 10* j;
for (int k = 0; k <=9 ;k++)
cout << arr[k] << " ";
cout << endl << endl;

arr[7] +=200;
arr[4] --;
arr[0] = 7;

return 0;
}

seems like it would take the values, respectively in each element, and modify them

the first case taking the value and adding 200 to it, the second case taking the value and decreasing it by one.

but what if is were to say that:

two = "baseball";
two[3]++;
two[4]='Q';
two[5]='9';
cout<<two<<endl;

what would it change it to?o.O

"basfQ9ll"

two[3]++;
adds one to the 'e'

two[4]='Q';
changes 'b' to 'Q'

two[5]='9';
changes 'a' to '9'

so u can ++ or -- still works for alphabets too, i see. ty!

how do you think alphabetical characters are represented in computers? They work similar to ASCII values iirc. So every letter, symbol etc has some sort of integer value associated with it. Thus adding '1' to 'e' does make sense.

This post was edited by Eep on Dec 9 2012 03:14pm

strictly speaking, it depends on the character encoding as well as the language.

yeah I forgot about the fact there are multiple encodings

decrementation in c++ is x-- not x-

and?

This post was edited by Eep on Dec 10 2012 12:30pm