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Parse error: syntax error, unexpected '(', expecting ')' in example.php on line 4

Quote (carteblanche @ Jul 16 2012 07:55pm)

afaik you can't use "var" as a member variable. try changing that to private/public/protected

otherwise stick that in your constructor

my php knowledge is extremely limited though.

Quote (carteblanche @ Jul 16 2012 07:59pm)

is Class supposed to be capitalized? i think php is lowercase, no?

/edit im looking at this
http://php.net/manual/en/language.oop5.basic.php

Quote (gtackle62 @ Jul 16 2012 09:03pm)

made it lowercase and it didn't change, I've also made classes w/ it uppercase before, I don't think it matters.

also used a function_exists() on the function name, returned true...

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Quote (DeadShell @ Jul 16 2012 08:21pm)

for some odd reason you can't do that

I guess you have to do something like this

Quote (gtackle62 @ 17 Jul 2012 04:23)

Figured I might have to :/ thought there might be a workaround or something though, guess I'll just have to do it in the constructor or something similar, thanks.

Quote (eagl3s1ght @ Jul 17 2012 06:14am)

Sure, why don't you want to?
http://codepad.viper-7.com/0RBGy7

Or you could just skip the whole class part. Don't use it if you don't need it.

Quote (DeadShell @ 17 Jul 2012 18:31)

What's the reason that you can't define a variable without putting it inside a function, I'm kind of curious now?

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http://stackoverflow.com/questions/6486660/unexpected-t-variable-expecting-t-function
This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.