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Mar 8 2016 05:27pm
Quote (Blankey @ 8 Mar 2016 00:00)
seeking further insight

so essentially nothing is perfectly round both in reality and in computed simulations


I think they made the most round object in the world recently attempting to make a new standard for the original metric system. Think it was some type of silocon they used. Pretty neat idea. Theres a youtube video of it somewhere just google most round object in the world or something like thay

Edit

https://youtu.be/ZMByI4s-D-Y

This post was edited by Version on Mar 8 2016 05:28pm
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Mar 15 2016 06:05pm
Quote (Version @ Mar 8 2016 07:27pm)
I think they made the most round object in the world recently attempting to make a new standard for the original metric system. Think it was some type of silocon they used. Pretty neat idea. Theres a youtube video of it somewhere just google most round object in the world or something like thay

Edit

https://youtu.be/ZMByI4s-D-Y



I saw that which made me think about this in general. Even in the case of that rl sphere its still not a true sphere; its a multi-faced polygon with an extremely high number of faces whose size/shape is dictated by the element/compound's chemical structure lattice. It was interesting to note the price of that ball ($1m or $10m?) even though it was just silicon like you said.

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Quote (carteblanche @ Mar 8 2016 03:23pm)
You can never see a circle for reasons they mentioned. But for computation purposes you can use perfect circles with respect to pi.


So if Pi is used say approximated a million decimals out the 'quasi sphere' still isn't a sphere correct? Just a quasi-sphere with a very high number of faces?



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Mar 15 2016 06:52pm
hence you can compute perfectly with respect to pi.
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Mar 15 2016 08:24pm
Quote (Blankey @ Mar 15 2016 05:05pm)
I saw that which made me think about this in general. Even in the case of that rl sphere its still not a true sphere; its a multi-faced polygon with an extremely high number of faces whose size/shape is dictated by the element/compound's chemical structure lattice.
Right. Just like to draw even a small circle on a computer screen requires an infinite number of pixels, which you don't have.

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Mar 16 2016 12:49am
Quote (carteblanche @ Mar 15 2016 08:52pm)
hence you can compute perfectly with respect to pi.


So in essence a computer can't compute it perfectly and must approximate it since pi will be rounded or be an infinitely long variable in which it can't compute it completely?
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Mar 16 2016 02:04am
Quote (Blankey @ Mar 15 2016 11:49pm)
So in essence a computer can't compute it perfectly and must approximate it since pi will be rounded or be an infinitely long variable in which it can't compute it completely?


compute it is kind of broad. You can calculate if a second point lies within, outside, or on the surface of the sphere. You can compute the exact volume of the sphere/pi. But if you want the exact volume as a rational number, you are in big trouble because the volume in most cases will not be rational. Which you can not print it out exactly on a computer screen as a decimal. And if you try to render it you are back to your infinitely sided polygon problem.
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Mar 16 2016 06:50am
Quote (Blankey @ Mar 15 2016 11:49pm)
So in essence a computer can't compute it perfectly and must approximate it since pi will be rounded or be an infinitely long variable in which it can't compute it completely?


yes, which is what I posted 100 times

if you take a square piece of paper and cut the corners with scissors that also will eventually form a circle that we can't tell it has corners..
for anything visual, what else matters? all that matters is our eyes can't see the corners. when it comes to that, it's "perfect"

with rounding pi your sphere is disproportionate.. but it really doesn't matter.

This post was edited by GRATS on Mar 16 2016 06:50am
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Mar 16 2016 10:25am
Quote (GRATS @ Mar 16 2016 08:50am)
yes, which is what I posted 100 times

if you take a square piece of paper and cut the corners with scissors that also will eventually form a circle that we can't tell it has corners..
for anything visual, what else matters? all that matters is our eyes can't see the corners. when it comes to that, it's "perfect"

with rounding pi your sphere is disproportionate.. but it really doesn't matter.



Thanks

I appreciate the answers all.
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Mar 16 2016 01:57pm
For that matter, I don't think you can have a perfect visual representation of lines either, so all polygons are out of the question too
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Mar 16 2016 02:02pm
Quote (carteblanche @ Mar 16 2016 02:57pm)
For that matter, I don't think you can have a perfect visual representation of lines either, so all polygons are out of the question too


These constructs are abstract concepts. Our mathematical models are always just approximations. Because if you could define it concretely it would cease to be abstract by definition.
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