When I run it, it doesn't run the when it asks for the bet amount.

there must be something in the buffer after one of your previous reads. It is using that as the value of nextLine();

right now my only other input is

How would I go about making it not read the previous input from that?

Your Scanner is wrapping whats known as an InputStream. The source of the InputStream is the console (System.in). That input stream will continue to accumulate and buffer data as long as you continue to enter it. When you invoke any of the next methods on the Scanner object, you are only removing whatever you asked for from that buffer. Everything else remains. In the case of nextInt(), it removes the next integer value within the stream.

So let's look at what you entered into the stream.

If you wanted to bet 100, you executed the following keystroke sequence 1 0 0 Enter. Now, you think you only buffered the value 100 into the stream, but that Enter resolves to a character value. On a Windows machine it will be a single newline character "\n", which represents a carriage return and a newline. On other OS's an Enter will actually result in 2 characters being added to the stream, a \r and a \n, because \n doesn't include the \r like it does in Windows.

But assuming you are on Windows, now your InputStream has buffered "100\n", so when you do your Scanner.nextInt() it will read the next integer from the buffer, or stop execution and wait for an input if none exists. So, after the nextInt() is completed, whats in the buffer for that InputStream? That's right, now the buffer contains "\n".

So what happens when you then do your again = keyboard.nextLine() statement? Well, nextLine() reads all character from the stream until it encounters a newline character, and returns that as your line. But there is already a new line in your buffer, which is the residual \n from your last input. So it doesn't need to wait for another line to be entered, it will just do that. So it reads that newline character as a line and returns the empty string to again.

So, how do you get around this? Well, there are two ways.

The first would be to do a flush on the Scanner to get rid of the newline. You can do this by calling keyboard.next() or keyboard.nextLine() after you do your keyboard.int(). This would flush that character, but at the cost of binding your implementation to manual console input. What if you wanted to redirect input from a file. Well now you have to put each number on a separate line to ensure there will be a newline character after each int. This might not be an issue, but I find it ugly.

My preferred solution is to do away with nextInt (as well as nextDouble, nextFloat, nextLong, etc), and instead just use nextLine() to read the value as a string and call the respective parse method for that value type.

I said this I said this I really Said this.

Thank you very much

I worded my response poorly, thankfully minko was there with the knowledge

hope you get it working