Iso Help With A Java Prob - Topic

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Oct 1 2014 02:52pm

So, my #1 problem was this and I works.

1. Write a program to read 5 integer numbers. If the number is between 1 and 500, calculate the square of that number and the cube of it. If its not between 1-500 , just don't do it.

Code

int iCinqNbr, iNbr, iCube, iCarre;
DecimalFormat df = new DecimalFormat("0.00");

for ( iCinqNbr = 0; iCinqNbr < 5; iCinqNbr++) {

iNbr=Integer.parseInt(JOptionPane.showInputDialog("Entrer une première valeur!"));

if (( iNbr >= 1) && ( iNbr <= 500 )){
iCarre=iNbr*iNbr;
iCube=iNbr*iNbr*iNbr;
System.out.println("Le carré de "+iNbr+" est de "+iCarre+" et son cube est de "+iCube+".");}
else
System.out.println("Le nombre restera le même.");

This works ..... now with my #2 , that's where I need help ..

I need to take this code, and make it so it doesn't calculate the square and cube if it's a multiple of 10.

Do I need to do another FOR or IF inside, im lost ..

BlindzF

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Oct 1 2014 03:02pm

Use modulus.

You're going to take the number you're checking against 10 and see if the remainder is 0. If it is then its a multiple of 10.

Jibbosh

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Oct 1 2014 06:00pm

Quote (Blind[zF] @ Oct 1 2014 05:02pm)

Use modulus.

You're going to take the number you're checking against 10 and see if the remainder is 0. If it is then its a multiple of 10.

Yup it works thanks.

I've got 1 last question in my homework that im blocking at a certain point.

I need to find the factorial of 1 to 10... which I did. But on my System.out ........... I need it to be like that : The Factorial of 4 is = 4*3*2*1

I just don't know how I can get the 4*3*2*1 with my code.

Code

int fact = 1, iValeur;
for (iValeur =1; iValeur <= 10; iValeur++) {

fact *= iValeur;

System.out.println("La valeur factorielle de "+iValeur+" est "+ "soit" +fact);
}

Aimed_Shot

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Oct 1 2014 06:35pm

Quote (Jibbosh @ Oct 1 2014 06:00pm)

Code

int fact = 1, iValeur;
for (iValeur =1; iValeur <= 10; iValeur++) {

fact *= iValeur;

System.out.println("La valeur factorielle de "+iValeur+" est "+ "soit" +fact);
}

I think..

Code

int fact = 1, i;
String temp = "";

for (i = 1; i <= 10; i++) {

fact *= i;

if (temp == "")
temp = i;
else
temp = i + "*" + temp;

System.out.println("The factorial of " + i + "is = " + temp);
}

carteblanche

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Oct 1 2014 06:41pm

Code

temp = i;

I'm not sure that compiles, but the logic looks about right. essentially build up a string in the loop, and only do a print statement once outside of the loop

Aimed_Shot

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Oct 1 2014 06:45pm

Quote (carteblanche @ Oct 1 2014 06:41pm)

Code

temp = i;

I'm not sure that compiles, but the logic looks about right. essentially build up a string in the loop, and only do a print statement once outside of the loop

fairly certain the compiler knows how to cast it

Jibbosh

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Oct 1 2014 06:51pm

Quote (Aimed_Shot @ Oct 1 2014 08:35pm)

I think..

Code

int fact = 1, i;
String temp = "";

for (i = 1; i <= 10; i++) {

fact *= i;

if (temp == "")
temp = i;
else
temp = i + "*" + temp;

System.out.println("The factorial of " + i + "is = " + temp);
}

With this, it tells me : temp= i cannot convert from int to string.

This post was edited by Jibbosh on Oct 1 2014 06:51pm

carteblanche

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Oct 1 2014 06:53pm

Quote (Aimed_Shot @ Oct 1 2014 08:45pm)

fairly certain the compiler knows how to cast it

Not in java. it would work in javascript though.

This post was edited by carteblanche on Oct 1 2014 06:58pm

Aimed_Shot

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Oct 1 2014 06:53pm

Quote (Jibbosh @ Oct 1 2014 06:51pm)

With this, it tells me : temp= i cannot convert from int to string.

Code

temp = Integer.toString(i);

e: i'm not sure if that's the most efficient way to cast it, but for looping 10 times it's fine lol

This post was edited by Aimed_Shot on Oct 1 2014 06:59pm

Jibbosh

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#10

Oct 1 2014 06:59pm

Quote (Aimed_Shot @ Oct 1 2014 08:53pm)

Code

temp = Integer.toString(i);

Works perfectly, thanks!

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