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Nov 1 2016 11:23pm


more proof that an object that is just moving consistently can be said to be experiencing "acceleration" (even though its not accelerating according to the English commonplace definition)

This post was edited by card_sultan on Nov 1 2016 11:26pm
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Nov 1 2016 11:31pm
Quote (card_sultan @ Nov 1 2016 09:23pm)
http://i.imgur.com/dKk3Mjr.jpg

more proof that an object experience that is just moving consistently and can be said to be experiencing "acceleration" (even though its not accelerating according to the English commonplace definition)

in your example the object is experiencing a change in velocity and is therefore experiencing acceleration(change in velocity is not 0 as you seem to claim in previous posts). Do you have a situation where an object can have 0 change in velocity but experience acceleration?
the term you may be looking for to represent a change in acceleration is a jerk
https://en.wikipedia.org/wiki/Jerk_(physics)

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Nov 1 2016 11:58pm
Quote (majorblood @ Nov 1 2016 07:31pm)
in your example the object is experiencing a change in velocity and is therefore experiencing acceleration(change in velocity is not 0 as you seem to claim in previous posts). Do you have a situation where an object can have 0 change in velocity but experience acceleration?
the term you may be looking for to represent a change in acceleration is a jerk
https://en.wikipedia.org/wiki/Jerk_(physics)


your completely stuck on the idea that the physics definition of acceleration is only just the english definition

an object does not have to be accelerating(<-----English definition) to be experiencing acceleration (physics definition)

look at this Centripetal acceleration of Earth around Sun Feb 3, 2008 #1 blue5t1053 Problem: The earth's orbit (assumed circular) around the sun is 1.5e11 m in radius, and it makes this orbit once a year. What is the centripetal acceleration of the earth? Equations: a = (v^2) / r T = (2*pi*r) / v My work: T = (2*pi*r) / v; 1 year = (365 days / 1 year)*(24 hours / 1 day)*(60 mins / 1 day)*(60 secs / 1 min) = 3.1536e7 s; 3.1536e7 s = (2*pi*1.5e11 m) / v; algebraically rearranged is: v = (2*pi*1.5e11 m) / (3.1536e7 s) v = 29885.8 m/s a = (v^2) / r; a = ((29885.8 m/s)^2) / (1.5e11 m); a = 0.005954 m/s^2 MY ANSWER

Reference https://www.physicsforums.com/threads/centripetal-acceleration-of-earth-around-sun.212860/

Is the earth speeding up is orbit around the sun every year - of course not

acceleration is just movement - not just speeding up

This post was edited by card_sultan on Nov 2 2016 12:01am
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Nov 2 2016 12:05am
Speed has no vector component, acceleration does. The Earth does not speed up around the sun, but it does accelerate.
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Nov 2 2016 12:13am
Quote (card_sultan @ Nov 1 2016 09:58pm)
your completely stuck on the idea that the physics definition of acceleration is only just the english definition

an object does not have to be accelerating(<-----English definition) to be experiencing acceleration (physics definition)

look at this Centripetal acceleration of Earth around Sun Feb 3, 2008 #1 blue5t1053 Problem: The earth's orbit (assumed circular) around the sun is 1.5e11 m in radius, and it makes this orbit once a year. What is the centripetal acceleration of the earth? Equations: a = (v^2) / r T = (2*pi*r) / v My work: T = (2*pi*r) / v; 1 year = (365 days / 1 year)*(24 hours / 1 day)*(60 mins / 1 day)*(60 secs / 1 min) = 3.1536e7 s; 3.1536e7 s = (2*pi*1.5e11 m) / v; algebraically rearranged is: v = (2*pi*1.5e11 m) / (3.1536e7 s) v = 29885.8 m/s a = (v^2) / r; a = ((29885.8 m/s)^2) / (1.5e11 m); a = 0.005954 m/s^2 MY ANSWER

Reference https://www.physicsforums.com/threads/centripetal-acceleration-of-earth-around-sun.212860/

Is the earth speeding up is orbit around the sun every year - of course not

acceleration is just movement - not just speeding up


acceleration is the change in velocity with respect to time. When will you understand this?
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Nov 2 2016 01:09am
Quote (majorblood @ Nov 1 2016 08:13pm)
acceleration is the change in velocity with respect to time. When will you understand this?


0 change is a change, when will you accept that zero is a value.

Zero is a number, and it holds a value in the same sense that any number holds a value.

https://en.wikipedia.org/wiki/0_(number)

0 (zero; BrE: /ˈzɪərəʊ/ or AmE: /ˈziːroʊ/) is both a number[1] and the numerical digit used to represent that number in numerals

if you really dont understand that 0 is a value, this conversation is really beyond your understanding.

anything with mass that is moving has force, what is an example of something that is moving (consistently/accelerating/decelerating)that has mass that has no force?

This post was edited by card_sultan on Nov 2 2016 01:13am
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Nov 2 2016 01:14am
Quote (card_sultan @ Nov 1 2016 11:09pm)
0 change is a change, when will you accept that zero is a value.

Zero is a number, and it holds a value in the same sense that any number holds a value.

https://en.wikipedia.org/wiki/0_(number)

0 (zero; BrE: /ˈzɪərəʊ/ or AmE: /ˈziːroʊ/) is both a number[1] and the numerical digit used to represent that number in numerals

if you really dont understand that 0 is a value, this conversation is really beyond your understanding.


What is the minimal net force required to have a change of exactly 0 m/s on an object?


Quote
anything with mass that is moving has force, what is an example of something that is moving (consistently/accelerating/decelerating)that has mass that has no force?

an object in motion stays in motion unless acted upon by a force. You do not need a force to be moving at constant velocity, in fact you need zero net force to maintain constant velocity.
refer to http://www.physicsclassroom.com/class/newtlaws/Lesson-1/Newton-s-First-Law

This post was edited by majorblood on Nov 2 2016 01:17am
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Nov 2 2016 02:31am
Quote (majorblood @ Nov 1 2016 09:14pm)
What is the minimal net force required to have a change of exactly 0 m/s on an object?



an object in motion stays in motion unless acted upon by a force. You do not need a force to be moving at constant velocity, in fact you need zero net force to maintain constant velocity.
refer to http://www.physicsclassroom.com/class/newtlaws/Lesson-1/Newton-s-First-Law


zero net force - does not mean no force

if it meant no force - it would say no force

in this case it means no new force, or no additional force - I also doesn't mean that the object doesn't have force

If you only new how much your embarrassing yourself - i can see why you resort to insulting people and thinking that means you won - you have nothing else.



This post was edited by card_sultan on Nov 2 2016 02:36am
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Nov 2 2016 02:43am
Quote (card_sultan @ Nov 2 2016 12:31am)
zero net force - does not mean no force

if it meant no force - it would say no force

in this case it means no new force, or no additional force - I also doesn't mean that the object doesn't have force

If you only new how much your embarrassing yourself - i can see why you resort to insulting people and thinking that means you won - you have nothing else.

http://www.youtube.com/watch?v=8rh6qqsmxNs


I am not insulting you. You have not answered my question. I know what net force means.
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Nov 2 2016 02:49am
Quote (card_sultan @ Nov 2 2016 10:31am)
zero net force - does not mean no force

if it meant no force - it would say no force

in this case it means no new force, or no additional force - I also doesn't mean that the object doesn't have force

If you only new how much your embarrassing yourself - i can see why you resort to insulting people and thinking that means you won - you have nothing else.

http://www.youtube.com/watch?v=8rh6qqsmxNs


Exactly how is he embarrassing himself, when pretty much all of d2jsp agrees with him and disagrees with you? Without getting into the discussion at hand, this is something I really would like you to explain to me.
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