Quote (Qodesh @ Jun 7 2016 12:05am)
Discernment is the hardest task you will ever face in your life. I pray for you, I am not saying this only to you, but it basically applies to everyone.
Take a tenis ball and soak it in water. Then make it spin in the air. What will happen to the water? From where will it go off the tenis ball? I think you need to think just a little to figure this one out...
To make sense of your idea we must assume the following equation is true and that acceleration due to gravity is -9.8m/s^2 at the surface of the earth. These calculations are going to be made at the equator.
a1 = v^2/r
where
a1= acceleration due to centrifugal force
v = velocity of rotation
r = radius of the earth (6378000m)
to determine the velocity of rotation we will take the circumference of the earth at the equator (known as 40074km in the spherical earth theory) and divide that by the time it takes for one full rotation (rounded to 24hours or 86400 seconds)
40074km / 86400 seconds = 0.46382 km/s or 463.82m/s
a1 = (463.82m/s)^2 / 6378000s
a1 = 0.034m/s^2
Now the net acceleration acting on the water in this system (assuming the centrifugal force is acting in the opposite direction of gravity) is the sum of the acceleration due to the centrifugal force and the acceleration due to gravity.
0.034m/s^2 + -9.8m/s^2 = -9.766m/s^2.
The acceleration due to centrifugal force is not enough to overcome the acceleration due to gravity and therefore the rotation of the Earth does not cause water to spray into outerspace.
This post was edited by majorblood on Jun 7 2016 04:13am