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Oct 21 2017 06:08pm
I missed a class dealing with some family stuff and my introduction networking class picked that day to go over the bulk of subnetting.

I've got an assignment I'm trying to figure out, but I have been unable to figure out the content by myself just reading through notes and I'm beginning to run out of time that I'll be able to spend on this assignment, without completely screwing myself for other classes.

Any help would be greatly appreciated. I don't necessarily want someone to fill in the answers, I'd much rather have someone just help me figure it out, but I know someone with knowledge of this stuff would be able to figure this out instantly.

172.50.0.0 -

Part 1 = 5 Hosts per subnet possible - I THINK I was able to figure this one out on my own, happy to discuss the answers I found over pm
Address class
Default Sub
Custom Sub
Bits Borrowed
Total Subnets
Usable Addresses per subnet
Usable address range for 3rd subnet
Subnet ID for the 5th subnet
Broadcast address for the 6th subnet -

Part 2 = Create a subnetting scheme using the fewest number of subnets possible

Address class
custom sub
number of subnets needed
total number of subnets provided by new mask
number of host addresses required in the largest subnet group
number of usable addresses per subnet provided by new mask
IP address range for Router F0/0 Port
IP address range for Router F0/1 Port

Part 3 = Create a subnetting scheme using the minimum number of hosts per subnet possible

Address class
custom sub mask
number of subs needed
total number of subs provided by new mask
number of host addresses per subnet provided by new mask
number of usable addresses per subnet provided by new mask
IP address range for router A Port F0/0
IP address range for research
IP address range for deployment
IP address range for Router A to Router B serial connection

Part 4 = Create an IPv6 subnetting scheme using : hierarchical addressing and subnettig on the nibble.

2001:EE00:2575::/48

Administration building Production building
Sales Casting
Accounting Distribution Editing


Infrastructure Site ID : 2001:ee00:2575
Administration Site ID: 2001:ee00:2575
Infrastructure sub-site ID: 2001:ee00:2575
Sales sub-site ID: 2001:ee00:2575
Accounting sub-site ID: 2001:ee00:2575
Distribution sub-site ID: 2001:ee00:2575
Production Site ID: 2001:ee00:2575
Infrastructure sub-site ID: 2001:ee00:2575
Casting sub-site ID: 2001:ee00:2575
Editing sub-site ID: 2001:ee00:2575


This should be fairly simple for someone who knows the material and I of course would be happy to pay for either someone to take the time to explain, or for someone to help me out with the answers. Thanks.
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Oct 22 2017 02:22pm
Anyone?
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Oct 23 2017 02:58am
IP address and subnets.
So IP address is 8 bits displayed on 4 octets in 0-255.
IPv4 ranges are: 0.0.0.0 - 255.255.255.255

You have two parts to an IP address. You have the Network Address and you have the Host Address. This is determined by the subnet mask.
If you go to Command Prompt and type in 'ipconfig' you will see your IP address and subnet mask.
My IP address is: 10.0.0.11 with subnet mask: 255.255.255.0.

So I have a Network address of 10.0.0.0 with the Host addresses ranging from 10.0.0.1 - 10.0.0.255.
Another way to write an IP address is: 10.0.0.11/24 which means the /24 is the 255.255.255.0 Subnet.

Now it just so happens that you can make the subnet mask whatever you want. You can have a total of 255 Host addresses to play with and you may want to further divide that into two or more networks.
Now with the way that subnetting works, you basically work in the power of 2's by doubling or halving.

0 - 255 is a total of 256. If I want 5 hosts I will need to have a subnet which will accept 8 total host addresses.
If I have a subnet mask of 255.255.255.128 then that Network has been split in two with 128 Host addresses each.

So if I want a network with a total of 5 host addresses the subnet mask will be 255.255.255.248 or 10.0.0.0/29. The next network address will be: 10.0.0.8/29 then 10.0.0.16/29 etc.

Now you can turn these octets into binary. I said before there are 8 bits in each octet. Binary works in 0 and 1.

255 = 11111111

Think of binary as:
128, 64, 32, 16, 8, 4, 2, 1
...1.....1....1...1..1..1..1..1

1 means on and 0 means off. If all the numbers are 1 then you add up the numbers and you will get 255.
So if I want to get 248 I will take the bits from left to right and try to get 248. So the last subnet in binary will be: 11111000 (128 + 64 + 32 + 16 + 8 = 248)

If you add 4 + 2 + 1 you will have a subnet with a total of 7 host addresses. You have to include the network address which will go up in multiple's of 8 so that's the extra host address.
10.0.0.0 is the Network address and 10.0.0.7 is the last available host address in that network if the subnet mask is 255.255.255.248. (Count up in multiple of 8 to determine each network address).
Now the very first address is the Network address and the very last address is the broadcast address. So every single network will have the grand total of useable addresses - 2 for the Network and broadcast address.
So when you have 8 useable addresses, you will be able to use 6 of those IP addresses for host addresses.

Once you understand this concept then you can use this cheat sheet for help.
https://kthx.at/subnetmask/

I hope this helps.
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Oct 23 2017 02:20pm
Willing to pay someone 1k fg for the answers at this point. I'm running out of time pretty hard.
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Oct 24 2017 05:37am
Well how many hosts per subnet do you need?

The largest subnet you will use is /30 which is 2 hosts between a link of two routers. You will have the Network address, two hosts and the broadcast address.

With part 2 and part 3, are you making it up on your own or are you given a number of required hosts per subnet?

Just think that you have a total of 255 host addresses to play with and you can separate them into different networks.

Also, was there something about my explanation that made no sense?
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Oct 24 2017 11:33am
Quote (CPK001 @ Oct 24 2017 03:37am)
Well how many hosts per subnet do you need?

The largest subnet you will use is /30 which is 2 hosts between a link of two routers. You will have the Network address, two hosts and the broadcast address.

With part 2 and part 3, are you making it up on your own or are you given a number of required hosts per subnet?

Just think that you have a total of 255 host addresses to play with and you can separate them into different networks.

Also, was there something about my explanation that made no sense?


I tried to pm you my questions, but your inbox is always full. The assignment is due 5 hours from now. I believe I have it finished, but would be incredibly grateful to have a knowledgeable individual review/check my answers if you're up for it. Just pm me if you can and I'll send you my email or w/e.
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