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Apr 9 2023 05:32pm
Quote (Neili @ 10 Apr 2023 01:07)
MY ANSWER :

Both event have a 1/30 chance to occur on 30 days , so both event have 8/30 chance to occur in these 8 days,

there is is 26,67% chance for 1 event to occur in one of these 8 days.

For both events to occur in one of these 8 days, (26,67/100) x (26,67/100) = 0,0711 = 7,11% ,

there is 2,13/30 chance both events occurs in these 8 days wich is 7,11%.


CHATGPT ANSWERS :

Your response is incorrect. The probability of one event occurring on one of the 8 days is 8/30. The probability of both events occurring on one of the 8 days is (8/30) * (8/30) = 64/900. As a percentage, this is approximately 7.11%. As a ratio, this is 64:900.

The probability of at least one event occurring on one of the 8 days is 1 - the probability that neither event occurs on one of the 8 days. The probability that neither event occurs on one of the 8 days is (22/30) * (22/30) = 484/900. So the probability that at least one event occurs on one of the 8 days is 1 - 484/900 = 416/900. As a percentage, this is approximately 46.22%. As a ratio, this is 416:900.

another answer from CHATGPT:

The probability of an event occurring on one of those 8 days can be calculated as follows:

Probability of event occurring on any given day = (number of days event can occur) / (total number of days)
Probability of event not occurring on any given day = (number of days event cannot occur) / (total number of days)
In this case, there are 30 - 8 = 22 days when the event can occur and 8 days when it cannot occur.

Therefore, the probability of the event occurring on one of those 8 days is:

Probability of event occurring on one of those 8 days = 1 - Probability of event not occurring on any given day

Probability of event not occurring on any given day = (number of days event cannot occur) / (total number of days)

Probability of event not occurring on any given day = 8 / 30

Probability of event not occurring on any given day = 0.2667

Probability of event occurring on one of those 8 days = 1 - Probability of event not occurring on any given day

Probability of event occurring on one of those 8 days = 1 - 0.2667

Probability of event occurring on one of those 8 days = 0.7333 or 73.33%

Therefore, the probability that the event will occur on one of those eight days is 73.33% or 11:3 as a ratio.





i was right since the beginning lmao , this robot do not say the same as me & with 3000 additional words

This post was edited by Neili on Apr 9 2023 05:50pm
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Apr 9 2023 11:19pm
Quote (Wieners @ Apr 10 2023 12:56am)
Need help, show working pls.

In 30 days, 2 events occur.
In those 30 days, there is 8 days you do NOT want the even to occur.

What are the chances the event will occur on one of those 8 days ?

Please and thankyou.

As a ratio and also a %


are you really interested or has this now turned into a chat gpt discussion? :D
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Apr 9 2023 11:41pm
Quote (PiXi31415 @ Apr 10 2023 03:19pm)
are you really interested or has this now turned into a chat gpt discussion? :D


I still want to know.

I don’t think it’s 70% chance , that seems way too high.

2 events in 30 days and the chances 1 of them lands on one of 8 possible days.

That’s like 1 out of 4 out of 15.

1/15 days it happens
4 of those 15 days you don’t want it to happen on.

Here’s what the situation is.

My friend is starting nightshift.
He will work 8 night shifts in 30 days
His son (on average) has a hospital visit twice every 30 days.

My mate is worried that while on nightshift, his son will have one of his episodes.
I believe the answer is much much less

This post was edited by Wieners on Apr 9 2023 11:51pm
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Apr 9 2023 11:48pm
lol moved to homework help hotline, GG :D
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Apr 9 2023 11:49pm
btw, is one of jsp's math wizard. He can probably help and clear all this up

This post was edited by ChocolateCoveredGummyBears on Apr 9 2023 11:49pm
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Apr 10 2023 12:53am
1) Is the question about the probability that NEITHER of the two events will occur on one of the 8 days? Or just that one, or at least one, will do?
2) Are the two events independent of each other? Can, in theory, both occur on the very same day?
3) Is the distribution over the 30 days uniform, i.e. does each of the 30 days have the same likelihood of being an event day?

Without these specifications you won't be able get a result fitting your problem.

Example: Assuming events are completely independent (can even happen on same day) and each day is equally likely.

a) Then the probability that neither of the two will be on one of the 8 days is 22/30 times 22/30 = 121/225 = 53.78 % (rounded). ---> Why? Each event can roll a number from 1 to 30. There are 8 numbers you don't want, so 22 of the 30 are good. Since we assumed independence and there's two events, you multiply the 22/30 with itself.
b ) The probability that at least one event is on one of the 8 is 1 - 121/225 = 104/224 = 46.22 % (that's the counter-event relative to the line above).
c) The probability that exactly one event is on one of the 8 and other event is on a good day is 22/30 * 8/30 * 2 = 88/225 = 39.11 %
d) Lastly, both events will take place on one of those 8 days with a probability of 8/30 * 8/30 = 16/225 = 7.11 %.

Different assumptions will lead to different results!

This post was edited by TheOnlyDenny on Apr 10 2023 12:53am
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Apr 10 2023 01:02am
Quote (TheOnlyDenny @ Apr 10 2023 04:53pm)
1) Is the question about the probability that NEITHER of the two events will occur on one of the 8 days? Or just that one, or at least one, will do?
2) Are the two events independent of each other? Can, in theory, both occur on the very same day?
3) Is the distribution over the 30 days uniform, i.e. does each of the 30 days have the same likelihood of being an event day?

Without these specifications you won't be able get a result fitting your problem.

Example: Assuming events are completely independent (can even happen on same day) and each day is equally likely.

a) Then the probability that neither of the two will be on one of the 8 days is 22/30 times 22/30 = 121/225 = 53.78 % (rounded). ---> Why? Each event can roll a number from 1 to 30. There are 8 numbers you don't want, so 22 of the 30 are good. Since we assumed independence and there's two events, you multiply the 22/30 with itself.
b ) The probability that at least one event is on one of the 8 is 1 - 121/225 = 104/224 = 46.22 % (that's the counter-event relative to the line above).
c) The probability that exactly one event is on one of the 8 and other event is on a good day is 22/30 * 8/30 * 2 = 88/225 = 39.11 %
d) Lastly, both events will take place on one of those 8 days with a probability of 8/30 * 8/30 = 16/225 = 7.11 %.

Different assumptions will lead to different results!


Interesting read, thankyou :hail:

And just for clarification:

1) atleast one
2) they cannot occur on same day. They are independent
3) yes, uniform
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Apr 10 2023 01:15am
The odd you're looking for is 68/145 = 46.90 % (rounded).

The probabilities of "at least one" and "none" should add up to 1, or 100 %, so let's look at "none of the two will on those 8 days"

There are 22 good days. Since the events can't occur on the same day, there are 22*21 = 462 "good" ways to place two events. (the "none" case)
In total, there are 30 days. So there are 30*29 = 870 ways to place the two events anywhere on the 30 day axis.

So the probability for "none" is 462/870 = 77/145.

But we were looking for "at least one", so it is in fact 1 - 77/145 = 68/145.

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Apr 12 2023 08:25am
=Prob(both events occur in the 8 days) + Prob(only first event occurs in the 8 days) + Prob(only second event occurs in the 8 days)= (8/30)*(8/30) + (8/30) * (22/30) + (22/30) * (8/30)

This post was edited by Princejosee on Apr 12 2023 08:25am
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