Quote (Hanako @ Jun 7 2018 02:22pm)
Your existence is incorrect, I can't really be arsed to find where it went in the wrong though (probably right at birth, even though you're now going to pretend you were trolling)
Now listen here, I'm always right, premed brainlet. As I said it depends on your definition of "intersect" for the green line but both of the lines I found definitely share the point B with the original polynomial curve and are tangent at a point (a,f(a)), which you did not bother to define so I could pick any a.
(and assuming Y is the plot line associated to y, which you did not define either)
(and assuming the tangent of f(x) at A is the tangent of f at A, else it is meaningless)
According to variations they are the only ones with these properties
http://i68.tinypic.com/f2owoi.pngand you're 25? damn, med students really are bainlets. The meme is actually true. I hope you fail because having doctors this slow being surgeons and shit is really scary.
There is nothing to know to solve this problem (the only prerequisites are extreme boredom and patience to try and understand your ill-stated problem which was supposed to be entertaining)
Mate, this isn't the kind of stuff I use -ever-. I browsed through it for 6 weeks for the MCAT and nothing remotely related to maths for the 5 years before that. I am human, I forget things. You would too.
If 13 is one solution you can find the other by factoring (x-13) out of x^3 - 11x^2 - 13 - p*x + 13p. Quotient is x^2 + 2x + (1-p). I think you'll find that p and q are both 0.
/e But I admit your answer looks pretty damn correct now that I bother to actually look at it lol, but I would define an intersection as "f(x) = g(x) /\ f ' (x) =/= g ' (x)", that is to say, their slopes differ. If they would not differ, it would not be an intersection but a tangent. But that's my interpretation.
This post was edited by Forg0tten on Jun 9 2018 03:09pm