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Feb 3 2018 03:31am
Quote (druidking88 @ Feb 3 2018 02:00am)
Fixed one small typo. You did the correct operation (addition) but stated the incorrect one (subtraction).

Yes, it is that easy when you get the hang of it! Nice work!


But isn't it supposed to be subtraction when the thing you are removing is positive? in this case 2x
and then addition when it's negative to get rid of it? :huh:
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Feb 3 2018 02:41pm
Quote (xaz @ Feb 3 2018 05:31am)
But isn't it supposed to be subtraction when the thing you are removing is positive? in this case 2x
and then addition when it's negative to get rid of it? :huh:


-2x is equivalent to + (-2x). Therefore you would need to add 2x to cancel it out to 0.

You could also use the fact that -(-2x) is equivalent to +2x if it makes it more clear to you (or what you were inferring by subtraction)
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Feb 4 2018 01:52pm
I cbf reading all the posts, but feel free to PM me with questions if any remain. I will be happy to help.
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Feb 5 2018 04:18am
Quote (druidking88 @ Feb 3 2018 10:41pm)
-2x is equivalent to + (-2x). Therefore you would need to add 2x to cancel it out to 0.

You could also use the fact that -(-2x) is equivalent to +2x if it makes it more clear to you (or what you were inferring by subtraction)


Ah shoot didn't see it was -2x my bad then it's addition ofc but yeah got same result anyways.

Ok now the real question is, how do I go from k form to general form if it's needed?

I got the other one under control, now I need to know how to go from y=kx+m to Ax+By+C=0
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Feb 6 2018 09:13am
Quote (xaz @ Feb 5 2018 11:18am)
Ah shoot didn't see it was -2x my bad then it's addition ofc but yeah got same result anyways.

Ok now the real question is, how do I go from k form to general form if it's needed?

I got the other one under control, now I need to know how to go from y=kx+m to Ax+By+C=0


It just tells you to have one side equal to zero. In the form of y = k*x + m (which, really, is the same as By = A*x + C) you just have to throw over y and you're done:
y = k*x + m --> 0 = k*x + m - y --> (rearrange) k*x - y + m = 0

In this case, A is equal to k; B is equal to -1; C is equal to m:

k*x + (-1)*y + m = 0 = a*x + b*y + m
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Feb 6 2018 02:14pm
Quote (Forg0tten @ Feb 6 2018 05:13pm)
It just tells you to have one side equal to zero. In the form of y = k*x + m (which, really, is the same as By = A*x + C) you just have to throw over y and you're done:
y = k*x + m --> 0 = k*x + m - y --> (rearrange) k*x - y + m = 0

In this case, A is equal to k; B is equal to -1; C is equal to m:

k*x + (-1)*y + m = 0 = a*x + b*y + m


how do you get a=k, b=-1 etc? i need a little more simplified version if you may, english is not my primary language though I do understand it fluently. Just not when it comes to math explanations I guess ^_^
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Feb 7 2018 06:18am
In the general form, Ax+By+C=0, A is the coefficient of x, B is the coefficient of y, and C is the constant.
In the k form, y = kx + m, k is the coefficient of x, and m is the constant. y will always have a coefficient of 1 is this form.

Taking the k form, you can move the y term to the other side with kx and m to get general form:

Code
y = kx + m
-y = -y
-------------------

0 = kx - y + m


Since y is now negative, it is understood to now have a -1 coefficient, while x still have a coefficient of k, and the constant m.
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