I read you have to put 'L' at the end of a Long variable

So i was wondering what to do when the value of long variable is an expression?

long myLong = (myByte * 10) + 50_000 + (myShort + myInt);


^I try to put 'L' at the end and it gives me an error

Nvm, i guess 'L' Is only needed for Static/numeric values

Incorrect. you put L at the end of literals, not variables.

that's what i meant :|

Typically you only put L at the end of a pure literal

long foo = 20.0L;

For your case, you might need to do -

long myLong = (myByte * 10L) + 50_000L + (myShort + myInt);

Tho, I would imagine even without those the compiler would do the right thing.

except you cant put 20.0 in a long since it's not a floating type but ya

Ah yea, typo my bad :D

So used to doing it with f lol

This post was edited by MemoryOfLight on Apr 24 2017 02:55pm