paid up to this point.

13
Since this is a frictionless problem, the velocity of the skier going down a hill and losing 10 meters of elevation, will be the same as if he fell off a 10 meter high tower (it will just take him longer to reach this velocity, because of the incline of the hill, but time is not part of the problem).

VelocitySquared = VelocityInitialSquared + 2 * acceleration * (PositionFinal - PositionInitial)

VelocityInital = 4 m/s
PositionFinal = 0
PositionInitial =10
acceleration = -9.8 m/s

V^2 = 4^2 + 2 * (-9.8) * (0 - 10)
V^2 = 16 + 2 * (-9.8) * (-10)
V^2 = 212
V = 14.560 m/s (rounds to 15 m/s)

im done with this. test went well. thansk for all the help.

basically you want jsp to do your homework for you


read the rules, thats not what this forum is for

it's not homework. its me needing to understand the work.
these are just practice questions that i dont understand.
gtfo my thread thanks

lol dang, too bad I saw this late. I could've answered all these.