Quote (GladiatorZ_BG @ Nov 6 2009 03:36am)
sigh still confused..
i need the exact formulas u used for questions 2
then u taking the numbers from the problem and inserting in formula so i can actually learn how to do it.... all ug ave me was figure out time then divide which is not really helping
break up velocity into vertical/horizontal components. (Vy and Vx respectively)
h = Vy*t - 4.9t^2. solve for t to find how long in air. : height = Height initial + Vy*t - 1/2 (9.81)t^2. the 9.81 is the acceleration of gravity.
from this formula, you can figure out hang time ( time in the air) and then if height initial = height final, the graph will be a parabola so at t/2, there will be a maximum height.
next equation:
distance = Vx*t
same as the height basically but in this case you have no acceleration in the x direction.
i am giving you the formulas i used and most classes do use. what are you unsure of yet?