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Jan 21 2014 05:21am
I need help with a math question
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Jan 21 2014 05:21am
Ill help you.
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Jan 21 2014 05:22am
its just under geography section
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Jan 21 2014 05:23am
Quote (Raze @ Jan 21 2014 03:21am)
Ill help you.


Thanks
(1/2)^x=8
How do I solve for x



From (x-1)^2 subtract (x-3)(x-1). The result is
A) (x-1)-(x-3)
B ) 2(x-1)
C) -2(x-1)
D) x(x-1)
Not sure why it made a guy with glasses.

This post was edited by Terminatorfan12 on Jan 21 2014 05:24am
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Jan 21 2014 05:29am
Stick it in your calculator, y1= (1/2)^x
y2=8


See where they cross


Deduce via division
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Jan 21 2014 05:32am
Quote (Terminatorfan12 @ 21 Jan 2014 11:23)
Thanks
(1/2)^x=8
How do I solve for x

x=-3

From (x-1)^2 subtract (x-3)(x-1). The result is
A) (x-1)-(x-3)
B ) 2(x-1)
C) -2(x-1)
D) x(x-1)
Not sure why it made a guy with glasses.


(x-1)(x-1)=x^2-2x+1
(x-3)(x-1)=x^2-4x+3

so the result is 2x-2 which is B

btw, the right forum is http://forums.d2jsp.org/forum.php?f=257

This post was edited by brmv on Jan 21 2014 05:36am
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Jan 21 2014 05:33am
Thanks guys.
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Jan 21 2014 05:35am
Quote (brmv @ Jan 21 2014 07:32am)
(x-1)(x-1)=x^2-2x+1
(x-3)(x-1)=x^2-4x+3

so the result is 2x-2


how did you get -3?


as far as I can tell (1/2)^ - 3 = .125

This post was edited by Ylem122 on Jan 21 2014 05:36am
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Jan 21 2014 05:35am
The answer is A
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Jan 21 2014 05:38am
I'm not sure i already put down the answer as
C
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