Quote (Dreeb @ Feb 10 2011 04:35pm)
Bestem (fog)(0), (fog)(1), (gof)(0) and (gof)(1) when:
f(x)=x-1/3-x
og
g(x)=x^2+1
Define (fog)(0), (fog)(1), (gof)(0) and (gof)(1) when:
f(x)=x-1 / 3-x
and
g(x)=x^2+1
/ = divide.
x^2 = powered by 2.
Do this, and get fg.
Code
(fog)(x) = f(g(x)) = f(x^2 + 1) = (x^2 + 1 - 1)/3-(x^2+1) = x^2/(2 - x^2)
(fog)(0) = 0^2/(2-0^2) = 0
(fog)(1) = (1^2)/(2 - 1^2) = 1
Use the same logic for the other problems too. Remember, fog(x) = f( g(x) ), so you need to put g(x) in the place of x in the function, f.