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Michael515
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#1
Jun 8 2011 05:09pm
Factor the following expression:
8s^4 + 20t^3 -28
vagn
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#2
Jun 8 2011 05:22pm
It IS in fact, factorised to his simple expression. Or you wanted to say 8t^4 + 20t ^3 - 28 ?
If there is for real an 's' and a 't', can't be factorised.
else
I guess you have to do a squared completion
JADENAG
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#3
Jun 8 2011 05:50pm
Sure you copied it right?
Kamikizzle
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#4
Jun 8 2011 05:52pm
Quote (Michael515 @ Jun 8 2011 04:09pm)
Factor the following expression:
8s^4 + 20t^3 -28
4*(2s^4+5t^3-7)
thats about as good as it gets
TradeShop
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#5
Jun 9 2011 08:13am
Quote (Michael515 @ 9 Jun 2011 02:09)
Factor the following expression:
8s^4 + 20t^3 -28
answer is 32. ^^
MarkRoy7
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#6
Jun 9 2011 04:04pm
Quote (TradeShop @ Jun 9 2011 10:13am)
answer is 32. ^^
Not sure if serious... There is two unknowns. t and s, can't solve unless one is given.
Swiftys
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#7
Jun 10 2011 02:35am
simultaenous equations maybe? or put into the form of..
MaynardJamesKeenan
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#8
Jun 11 2011 12:57am
Quote (MarkRoy7 @ Jun 9 2011 03:04pm)
Not sure if serious... There is two unknowns. t and s, can't solve unless one is given.
Not sure if srs... There has to be an actual equation to solve for ANY variables...
TradeShop
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#9
Jun 11 2011 08:29am
Quote (MaynardJamesKeenan @ 11 Jun 2011 09:57)
Not sure if srs... There has to be an actual equation to solve for ANY variables...
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